2021
12-14
12-14
C++实现LeetCode(172.求阶乘末尾零的个数)
[LeetCode]172.FactorialTrailingZeroes求阶乘末尾零的个数Givenaninteger n,returnthenumberoftrailingzeroesin n!.Example1:Input:3Output:0Explanation: 3!=6,notrailingzero.Example2:Input:5Output:1Explanation: 5!=120,onetrailingzero.Note: Yoursolutionshouldbeinlogarithmictimecomplexity.Credits:Specialthanksto @ts foraddingthispr...
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